RRB NTPC CBT 2 Level 6 May-2-2022 Shift 1 Exam Previous Question Paper with Solutions
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Explanation:To find the HCF (Highest Common Factor) of 245, 175, and 385 using a shortcut method, follow these steps:
Step 1: Identify the common factors between the numbers quickly.
Step 1. Look for divisibility by small numbers:
– All the given numbers 245, 175, 385 are divisible by 5 (since each ends in 5).
Step 2. Divide by 5:
– ( 245 ÷ 5 = 49 )
– ( 175 ÷ 5 = 35 )
– ( 385 ÷ 5 = 77 )
Now we are left with the numbers 49, 35, and 77.
Step 2: Find the HCF of 49, 35, and 77.
Factorize these numbers:
– ( 49 = 7 × 7 )
– ( 35 = 5 × 7 )
– ( 77 = 7 × 11 )
The common factor is 7.
Step 3: Multiply the common factors:
– From Step 1, we divided by 5.
– From Step 2, the common factor is 7.
So, the HCF is:
HCF = 5 × 7 = 35
Conclusion:
The HCF of 245, 175, and 385 is 35.
Thus, the correct answer is 35.
2) Six people A, B, C, D, E and F are sitting around a circular table facing the centre. B sits second to the right of E. C sits to the immediate left of E. F sits second to the right of D. Who sits third to the right of A?
A) D
B) C
C) E
D) B
View Answer
A) D
Explanation:To solve this problem more efficiently using a shortcut method, let’s focus on the key clues provided and use a quick logical process to place the people around the table.
Key Clues:
»1. B sits second to the right of E.
»2. C sits to the immediate left of E.
»3. F sits second to the right of D.
Step-by-Step Shortcut:
»1. Positioning E:
– Since the problem doesn’t specify where to start, let’s assume E sits at position 1.
– C is immediately left of E, so C will be at position 6 (since it’s a circular table and left means one step counterclockwise).
»2. Positioning B:
– B sits second to the right of E. If E is at position 1, counting two places to the right (clockwise), B will be at position 3.
»3. Positioning F and D:
– F sits second to the right of D. To avoid conflicts, place D at position 4 and F will be at position 5.
»4. Remaining Person A:
– The only remaining empty spot is position 2, so A must sit there.
Final Seating Arrangement:
– Position 1: E
– Position 2: A
– Position 3: B
– Position 4: D
– Position 5: F
– Position 6: C
Who sits third to the right of A?
– Starting from A (position 2), the third seat to the right (clockwise) is D, who is seated at position 4.
Final Answer:
The person who sits third to the right of A is D.
3) Find the value of , where k is average of 16, 25, 13, 26 and 15.
A) 10
B) 8
C) 7
D) 9
View Answer
C) 7
Explanation:To find the value of , where ( k ) is the average of the numbers 16, 25, 13, 26, and 15, let’s follow the steps.
Step 1: Calculate the average value ( k )
The average of a set of numbers is the sum of the numbers divided by the number of values.
The numbers given are: ( 16, 25, 13, 26, 15 ).
The sum of these numbers is:
16 + 25 + 13 + 26 + 15 = 95
There are 5 numbers, so the average ( k ) is:
Step 2: Substitute ( k = 19 ) into (
4) In a certain code language, ‘RELATIONS’ is written as TSRONLIEA’, and ‘NUMBER’ is written as ‘URNMEB’.
How will ‘SPECULATION’ be written in that language?
A) UTSPONLIECA
B) UTNLIESPOCA
C) OCAATNLIESP
D) UOCATNLIESP
View Answer
A) UTSPONLIECA
Explanation:Now, let’s apply the same pattern to SPECULATION:
Break SPECULATION into individual letters:
S, P, E, C, U, L, A, T, I, O, N
Based on the previous examples, the pattern appears to involve swapping groups of letters in a specific order:
After rearranging the letters, we get the following transformed order: UTSPONLIECA
Thus, SPECULATION will be written as UTSPONLIECA in the code language.
5) The Champaran Satyagraha took place in the year _______