NMMS Exam 2018 Previous Year Question Paper with Answers And Complete Analysis With Key For Practice Test Paper

MATHEMATICS

Q). The largest number of four digits exactly divisible by 12, 15, 18 and 27 is
A) 8648
B) 9720
C) 6782
D) 5642

View Answer

B) 9720
Explanation: LCM of LCM of 12, 15, 18, 27
LCM=540
9999/540
Required number = 9999 – 279 = 9720

Q). If a679b is a five digit number that is divisible by 72, then the value of a + b is
A) 5
B) 8
C) 7
D) 6

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A) 5
Explanation: a679b =a+6+7+9+b
= 22 + a + b ‘—– (1)
a679b ——(2)
From (1) the number is divisible by 9.
From (2) last 3 digit divisible by 8 is the number divisible by 8.
Possible values b = 2, a = 3
a + b = 5

Q). if 154/69 is expressed as $a+\frac1{b\;+{\displaystyle\frac1{c+{\displaystyle\frac1d}}}}$ then the value of (c + d)-(a + b), when a, b, c, d are integers.
A) 4
B) 5
C) 6
D) 2

View Answer

D) 2
Explanation: a = 2, b = 4, c = 3, d – 5
∴ (c + d) -(a + b) = (3 + 5) -(2 + 4) = 2

Q. if x : y = 3 : 4, then the value of (4x – y) : (2x + 3y) is
A) 4:9
B) 8:9
C) 4:3
D) 8:3

View Answer

A) 4:9
Explanation: x/y=3/4
x = 3k, y = 4k
= 4x -y/2x + 3y
=12k – 4k/6k + 12k
8k/18k =4/9 =4:9

Q). If x + y + z = 0, then $\frac{x^2}{yz}+\frac{y^2}{zx}+\frac{z^2}{xy}$
A) √3
B) 3√3
C) 2
D) 0
E) 3

View Answer

E) 3
Explanation: x + y + z = 0
$\frac{x^2}{yz}+\frac{y^2}{zx}+\frac{z^2}{xy}$

$\frac{x^3+y^3+z^3}{xyz}$

3xyz/xyz =3

Q). if 2ⁿ-2^n-1 =4 , then the value of nⁿ will be
A) 1
B) 3/2
C) 2
D) 27

View Answer

D) 27
Explanation: 2ⁿ-2^n-1 =4
$\begin{array}{l}2^n\;-\frac{2^n}2=4\;\\2^n\left(1-\frac12\right)=4\;\\2^n=8\;,\\\;2^n=2^3,\\n=3\;,\\so\;n^n=3^3=27\end{array}$

Q). The ratio (of) between diagonals of two squares is 2: 1, then the ratio between their areas will be
A) 2:1
B) 4:1
C) 3:1
D) 6:1

View Answer

B) 4:1

Q). $\frac{\left(3.63\right)^2-\left(2.37\right)^2}{3.63\;+\;2.37}$ is simplified to
A) 6
B) 1.36
C) 2.26
D) 1.26

View Answer

D) 1.26
Explanation: $\frac{(3.63)^2\;-(2,37)^2}{3.63\;+\;2.37\;}\;\\=\frac{(3.63+2,37)\;(3.63-2.37)}{(3.63\;+\;2.37)}\\=\frac{6.00x1.26}{6.00}\\=1.26$

Q). Simplest form of the expression $\left(x^6.y^\frac{-5}4\right)^\frac{-4}3$ will be
A) $x^{-2}.y^4$
B) $x^{-8}.y^\frac53$
C) $x^{8}.y^\frac{-5}3$
D) $x^{-8}.y^\frac{-5}3$