RRB NTPC CBT 2 Level 6 May-2-2022 Shift 1 Exam Previous Question Paper with Solutions

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61) As of December 2021, the total number of nuclear power plants in India is________

A) 7
B) 9
C) 6
D) 10

View Answer

A) 7

62) The difference between the interest payable on a sum invested for three years at 20% compound interest per annum compounded annually and 20% simple interest per annum for the same period is ₹448. What is the value of the sum invested?

A) ₹3,750
B) ₹4,000
C) ₹3,500
D) ₹3,000

View Answer

C) ₹3,500

Explanation:We are given that the difference between the compound interest and simple interest for 3 years at 20% per annum is ₹448. We need to find the sum invested (the principal).
Step 1: Formulas for Simple Interest and Compound Interest
»1. Simple Interest (SI):
$\text{SI} = \frac{P × R × T}{100}$
Where:
– ( P ) is the principal,
– ( R ) is the rate of interest per annum,
– ( T ) is the time period in years.
»2. Compound Interest (CI):
$\text{CI} = P \left( 1 + \frac{R}{100} \right)^T - P$
Where:
– ( P ) is the principal,
– ( R ) is the rate of interest per annum,
– ( T ) is the time period in years.
Step 2: Simple Interest for 3 Years
We are given the rate $( R = 20\% )$ and time $( T = 3 )$ years. So, the formula for Simple Interest becomes:
$\text{SI} = \frac{P × 20 × 3}{100} = \frac{60P}{100} = 0.6P$
Step 3: Compound Interest for 3 Years
For Compound Interest, the formula is:
$\text{CI} = P \left( 1 + \frac{20}{100} \right)^3 - P = P \left( 1.2 \right)^3 - P$
First, calculate $( (1.2)^3 )$ :
$(1.2)^3 = 1.728$
So, the Compound Interest becomes:
CI = P × 1.728 – P = P(1.728 – 1) = 0.728P
Step 4: Difference Between Compound Interest and Simple Interest
The difference between Compound Interest and Simple Interest is given as ₹448. So:
0.728P – 0.6P = 448
0.128P = 448
$P = \frac{448}{0.128} = 3500$
Final Answer:
The value of the sum invested is ₹3,500.

63) Which of following enzymes is used in the stabilisation of rice bran oil?

A) Hydrolase
B) Catalase
C) Lipase
D) Cellulase

View Answer

C) Lipase

64) The ratio between the marked price and the cost price of an article is 5: 3. If the selling price of the article is ₹3,024 and the shopkeeper gave two successive discounts of 16% and 20%, then how much is the profit or loss (in ₹)?

A) Profit,₹324
B) Loss,₹112
C) Loss,₹216
D) Profit,₹225

View Answer

A) Profit,₹324

Explanation:Step-by-Step Solution:
We are given the following:
– The ratio between the marked price (MP) and the cost price (CP) is 5:3.
– The selling price (SP) of the article is ₹3,024.
– The shopkeeper gives two successive discounts of 16% and 20%.
We need to find whether there is a profit or loss and the amount.
Step 1: Relationship between Marked Price and Cost Price
Let the cost price (CP) be ( C ).
The marked price (MP) is given as:
$\frac{MP}{CP} = \frac{5}{3}$
So, we can express the marked price as:
$MP = \frac{5}{3} × C$
Step 2: Successive Discounts
First, the shopkeeper gives a 16% discount on the marked price. After the first discount, the price becomes:
Price after first discount = MP × (1 – 0.16) = MP × 0.84
Then, a 20% discount is applied on the reduced price. The final selling price is:
Selling Price = Price after first discount × (1 – 0.20) = MP × 0.84 × 0.80 = MP × 0.672
We are told that the selling price (SP) is ₹3,024. Therefore, we can write:
MP × 0.672 = 3,024
Solving for ( MP ):
MP = \frac{3,024}{0.672} = 4,500
Step 3: Calculate the Cost Price
Now, we know the marked price (MP) is ₹4,500. From the ratio between MP and CP, we have:
$MP = \frac{5}{3} × CP$
Substituting the value of ( MP ):
$4,500 = \frac{5}{3} × CP$
Solving for ( CP ):
$CP = \frac{4,500 × 3}{5} = 2,700$
Step 4: Calculate the Profit or Loss
The cost price (CP) is ₹2,700, and the selling price (SP) is ₹3,024.
The profit is:
Profit} = SP – CP = 3,024 – 2,700 = 324
Final Answer:
There is a profit of ₹324.