RRB NTPC CBT 2 Level 6 May-2-2022 Shift 1 Exam Previous Question Paper with Solutions

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36) As per Human Development Index Ranking (2020), which country has highest life expectancy at birth (years)?

A) Norway
B) France
C) Hong Kong, China (SAR)
D) Denmark

View Answer

C) Hong Kong, China (SAR)

37) In Contemporary Carnatic music, how many Melakarta ragas are there?

A) 72
B) 82
C) 62
D) 52

View Answer

A) 72

38) Which of the following options is the closest approximate value which will come in place of question mark(?) in the following equation?
499.37+ 1.95 × 4.79 – 2.87 ÷ 19.70=?

A) 510
B) 365
C) 290
D) 750

View Answer

A) 510

Explanation:Let’s simplify the equation step by step:
Equation:
499.37 + 1.95 × 4.79 – 2.87 ÷ 19.70
Step 1: Multiplication
First, let’s multiply $( 1.95 × 4.79 )$ .
1.95 × 4.79 = 9.3205
Step 2: Division
Next, let’s divide $( 2.87 ÷ 19.70 )$ .
$2.87 ÷ 19.70 \approx 0.145$
Step 3: Combine the results
Now, we can substitute the values into the original equation:
499.37 + 9.3205 – 0.145 = 499.37 + 9.1755 = 508.5455
Step 4: Check the closest answer
The approximate value of the expression is 508.55. Looking at the options, none of them are exactly this value, but the closest option is: 510

39) If 2sin y + cos y = √5 sin y, then find the value of tan y.

A) √5-1
B) √5-2
C) √5+2
D) √5+1

View Answer

C) √5+2

Explanation:We are given the equation:
$2\sin y + \cos y = \sqrt{5} \sin y$
We need to find the value of ( \tan y ).
Step 1: Rearrange the given equation
Let’s isolate the terms involving ( \sin y ) and ( \cos y ).
$2\sin y + \cos y = \sqrt{5} \sin y$
Subtract ( 2\sin y ) from both sides:
$\cos y = \sqrt{5} \sin y - 2\sin y$
Factor out ( sin y ) on the right-hand side:
$\cos y = (\sqrt{5} - 2) \sin y$
Step 2: Divide both sides by ( sin y )
Now, divide both sides of the equation by $( \sin y ) (assuming ( \sin y \neq 0 ))$ :
$\frac{\cos y}{\sin y} = \sqrt{5} - 2$
The left-hand side is the definition of $( \cot y )$ , so we get:
$\cot y = \sqrt{5} - 2$
Step 3: Find $( \tan y )$
Since $( \cot y = \frac{1}{\tan y} )$ , we can rewrite the equation as:
$\frac{1}{\tan y} = \sqrt{5} - 2$
Taking the reciprocal of both sides:
$\tan y = \frac{1}{\sqrt{5} - 2}$
Step 4: Rationalize the denominator
To rationalize the denominator, multiply both the numerator and the denominator by $( \sqrt{5} + 2 )$ :
$\tan y = \frac{1}{\sqrt{5} - 2} × \frac{\sqrt{5} + 2}{\sqrt{5} + 2} = \frac{\sqrt{5} + 2}{(\sqrt{5})^2 - 2^2}$
$\tan y = \frac{\sqrt{5} + 2}{5 - 4} = \sqrt{5} + 2$
Final Answer:
The value of $( \tan y )$ is $( \sqrt{5} + 2 )$ .

40) Select the option that is related to the fifth letter-cluster in the same way as the second letter-cluster is related to the first letter-cluster and the fourth letter-cluster is related to the third letter-cluster.
MDT: PAW :: RFQ : UCT :: LSK : ?

A) JPH
B) HRN
C) OPN
D) ORH

View Answer

C) OPN

Explanation:Let’s break down the given analogy step by step to determine the relationship between the clusters:
Given analogy:
MDT : PAW :: RFQ : UCT :: LSK : ?
Step 1: Analyzing the first part of the analogy: MDT → PAW
Let’s examine the transformation of each letter:
1. M → P: M is the 13th letter of the alphabet, and P is the 16th letter. This is an increase by 3 positions.
2. D → A: D is the 4th letter, and A is the 1st letter. This is a decrease by 3 positions.
3. T → W: T is the 20th letter, and W is the 23rd letter. This is an increase by 3 positions.
So, we can see that:
– The 1st and 3rd letters increase by 3 positions.
– The 2nd letter decreases by 3 positions.
Step 2: Analyzing the second part of the analogy: RFQ → UCT
Now, let’s apply the same rule to RFQ → UCT:
1. R → U: R is the 18th letter, and U is the 21st letter. This is an increase by 3 positions.
2. F → C: F is the 6th letter, and C is the 3rd letter. This is a decrease by 3 positions.
3. Q → T: Q is the 17th letter, and T is the 20th letter. This is an increase by 3 positions.
So, the same pattern of increasing by 3 for the 1st and 3rd letters and decreasing by 3 for the 2nd letter holds true here as well.
Step 3: Apply the same pattern to LSK:
Now, let’s apply the same pattern (increase by 3 for the 1st and 3rd letters, decrease by 3 for the 2nd letter) to LSK:
1. L → O: L is the 12th letter, and O is the 15th letter. This is an increase by 3 positions.
2. S → P: S is the 19th letter, and P is the 16th letter. This is a decrease by 3 positions.
3. K → N: K is the 11th letter, and N is the 14th letter. This is an increase by 3 positions.
Step 4: Conclusion
Thus, the letter-cluster that corresponds to LSK based on the same pattern is OPN.
The correct answer is:
OPN

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