TET Paper 1 Mathematics Content Bits Previous year question Paper Key with solutions

TET Paper 1 Mathematics Content Bits Previous year question Paper Key with solutions
Previous year question Paper Key with solutions 2024 Paper 1 Child Development and Pedagogy for TS TET Andhra Pradesh (AP) are very important objective multiple-choice questions for TET, DSC in Telangana, Andhra Pradesh based on D.Ed., B.Ed. books and schoolbooks. This previous paper of Tet paper 1 previous year question paper with answers is very useful for students to get good score in TS TET, AP TET, TS DSC, AP DSC TRT CTET examination.
TET PREVIOUS PAPERS AND GRAND TESTS


TS TET
PAPER 1
Previous Papers
Mathematics Content

91) The mean of first ten whole numbers is:
మొదటి పది పూర్ణాంకాల సగటు:

A) 5.25
B) 4.5
C) 5.5
D) 4.25

View Answer
B) 4.5

Explanation:The first ten whole numbers are: 0, 1, 2, 3, 4, 5, 6, 7, 8, and 9.
To find the mean (average):
Sum the numbers:0 + 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 = 45
Divide by the number of terms:
There are 10 numbers, so divide the sum by 10:
Mean = \frac{45}{10} = 4.5

92) The additive inverse of the expression (4m2 – 8m + 3) is:
(4m2 – 8m + 3) యొక్క సంకలన విలోమము:

A) 4m2 + 8m – 3
B) -4m2 – 8m – 3
C) 4m2 – 8m – 3
D) -4m2 + 8m – 3

View Answer
D) -4m2 + 8m – 3

Explanation:The additive inverse of an expression is obtained by changing the signs of all the terms in the expression.
Given the expression:4m2 – 8m + 3To find the additive inverse, we change the sign of each term:
– The additive inverse of 4m2 is -4m2.
– The additive inverse of -8m is +8m.
– The additive inverse of +3 is -3.
Therefore, the additive inverse of 4m2 – 8m + 3 is:
-4m2 + 8m – 3

93) The HCF of 32, 48 and 60 is:
32, 48 మరియు 60 ల యొక్క గ.సా.భా.:

A) 3
B) 6
C) 4
D) 8

View Answer
C) 4

Explanation:To find the HCF (Highest Common Factor) of 32, 48, and 60, we can use the prime factorization method.
Step 1: Prime Factorization of Each Number
– 32:( 32 = 25 )
– 48:( 48 = 24 X 3 )
– 60:( 60 = 22 X 3 X 5 )
Step 2: Identify the Common Factors
The only common prime factor among all three numbers is 2.
Now, take the lowest power of 2 that appears in all three factorizations:
– In ( 32 = 25 ), the power of 2 is 5.
– In ( 48 = 24 ), the power of 2 is 4.
– In ( 60 = 22 ), the power of 2 is 2.
The lowest power of 2 is 22.
Step 3: Conclusion
The HCF of 32, 48, and 60 is: 4

94) If the radius of outer circle is ‘R’ and inner circle is ‘r’ then the formula for area of a circular path ‘A’ is:
బాహ్య వృత్త వ్యాసార్థం ‘R’ మరియు అంతర వృత్త వ్యాసార్థం ‘7’ అయిన, కంకణాకార స్థల వైశాల్యము ‘A’ నకు సూత్రం:

A) А = π(R2 – r2)
B) А = π(R – г)(R − r)
C) А = π(R2 + r2)
D) А = π(R + r) (R + r)

View Answer
A) А = π(R2 – r2)

95) Pythagorean triplet in the following is:
క్రింది వానిలో పైథాగోరియన్ త్రికం:

A) (9, 40, 43)
B) (12, 33, 35)
C) (8, 15, 17)
D) (7, 25, 27)

View Answer
C) (8, 15, 17)

Explanation:A Pythagorean triplet consists of three positive integers a,b,c such that:
a2 + b2 = c2Let’s check each of the given triplets:(8, 15, 17)
Check if ( 82 + 152 = 172 ):
82 = 64,152 = 225,
172 = 28964 + 225 = 289,
289 = 289
So, (8, 15, 17) is a Pythagorean triplet.

Spread the love

Leave a Reply

Your email address will not be published. Required fields are marked *

Solve : *
33 ⁄ 11 =