TET Paper 1 Mathematics Content Bits Previous year question Paper Key with solutions
Previous year question Paper Key with solutions 2024 Paper 1 Child Development and Pedagogy for TS TET Andhra Pradesh (AP) are very important objective multiple-choice questions for TET, DSC in Telangana, Andhra Pradesh based on D.Ed., B.Ed. books and schoolbooks. This previous paper of Tet paper 1 previous year question paper with answers is very useful for students to get good score in TS TET, AP TET, TS DSC, AP DSC TRT CTET examination.
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PAPER 1
Previous Papers
Mathematics Content
91) The mean of first ten whole numbers is:
మొదటి పది పూర్ణాంకాల సగటు:
A) 5.25
B) 4.5
C) 5.5
D) 4.25
View Answer
B) 4.5
Explanation:The first ten whole numbers are: 0, 1, 2, 3, 4, 5, 6, 7, 8, and 9.
To find the mean (average):
Sum the numbers:0 + 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 = 45
Divide by the number of terms:
There are 10 numbers, so divide the sum by 10:
Mean = = 4.5
92) The additive inverse of the expression (4m2 – 8m + 3) is:
(4m2 – 8m + 3) యొక్క సంకలన విలోమము:
A) 4m2 + 8m – 3
B) -4m2 – 8m – 3
C) 4m2 – 8m – 3
D) -4m2 + 8m – 3
View Answer
D) -4m2 + 8m – 3
Explanation:The additive inverse of an expression is obtained by changing the signs of all the terms in the expression.
Given the expression:4m2 – 8m + 3To find the additive inverse, we change the sign of each term:
– The additive inverse of 4m2 is -4m2.
– The additive inverse of -8m is +8m.
– The additive inverse of +3 is -3.
Therefore, the additive inverse of 4m2 – 8m + 3 is:
-4m2 + 8m – 3
93) The HCF of 32, 48 and 60 is:
32, 48 మరియు 60 ల యొక్క గ.సా.భా.:
A) 3
B) 6
C) 4
D) 8
View Answer
C) 4
Explanation:To find the HCF (Highest Common Factor) of 32, 48, and 60, we can use the prime factorization method.
Step 1: Prime Factorization of Each Number
– 32:( 32 = 25 )
– 48:( 48 = 24 X 3 )
– 60:( 60 = 22 X 3 X 5 )
Step 2: Identify the Common Factors
The only common prime factor among all three numbers is 2.
Now, take the lowest power of 2 that appears in all three factorizations:
– In ( 32 = 25 ), the power of 2 is 5.
– In ( 48 = 24 ), the power of 2 is 4.
– In ( 60 = 22 ), the power of 2 is 2.
The lowest power of 2 is 22.
Step 3: Conclusion
The HCF of 32, 48, and 60 is: 4
94) If the radius of outer circle is ‘R’ and inner circle is ‘r’ then the formula for area of a circular path ‘A’ is:
బాహ్య వృత్త వ్యాసార్థం ‘R’ మరియు అంతర వృత్త వ్యాసార్థం ‘7’ అయిన, కంకణాకార స్థల వైశాల్యము ‘A’ నకు సూత్రం:
A) А = π(R2 – r2)
B) А = π(R – г)(R − r)
C) А = π(R2 + r2)
D) А = π(R + r) (R + r)
View Answer
A) А = π(R2 – r2)
95) Pythagorean triplet in the following is:
క్రింది వానిలో పైథాగోరియన్ త్రికం:
A) (9, 40, 43)
B) (12, 33, 35)
C) (8, 15, 17)
D) (7, 25, 27)
View Answer
C) (8, 15, 17)
Explanation:A Pythagorean triplet consists of three positive integers a,b,c such that:
a2 + b2 = c2Let’s check each of the given triplets:(8, 15, 17)
Check if ( 82 + 152 = 172 ):
82 = 64,152 = 225,
172 = 28964 + 225 = 289,
289 = 289
So, (8, 15, 17) is a Pythagorean triplet.