TS Polycet (Polytechnic) 2015 Previous Question Paper with Answers And Model Papers With Complete Analysis


Section – II
PHYSICS

Q). Read the following two statements and pick the correct answer:
a) Light travels in straight line.
b) Geometric centre of a concave mirror is called centre of curvature.
A) Only (a) is true
B) Only (b) is true
C) Both (a) and (b) are true
D) Both (a) and (b) are false

View Answer
A) Only (a) is true

Q). Focal length of a lens depends on
A) material of the lens
B) radius of curvature
C) Both material of the lens and radius of curvature
D) None

View Answer
C) Both material of the lens and radius of curvature

Q). The angle of refraction of a light ray is the angle between
A) incident ray and refracted ray
B) refracted ray and interface separating the two media
C) normal ray and incident ray
D) normal ray and refracted ray

View Answer
D) normal ray and refracted ray

Q). The extent of the change in the direction that takes place when a light ray travels from one medium to another is given by
A) critical angle
B) focal length
C) refractive index
D) focal power

View Answer
C) refractive index

Q). The refractive index of a material is 1. If the speed of light in vacuum is 3×108 m/s, then the speed of light in that material is
A) 0.3 x108m/s
B) 3×108m/s
C) 4 x108m/s
D) 108m/s

View Answer
B) 3×108m/s
Explanation: Speed of light in material
= Speed of light in vaccum/Index of a material
= 3 x 108/1 m/s
= 3 x 108 m/s

Q). In which of the following cases of convex lens, a virtual image is formed?
A) When the object is placed at the centre of curvature
B) When the’ object is placed beyond the centre of curvature
C) When the object is placed between the centre of curvature and focal point
D) When the object is placed between the focal point and optic centre

View Answer
D) When the object is placed between the focal point and optic centre

Q). A curved surface of radius of curvature R is separating the two media of refractive indices n1 and n2. If u and v are object and image distances respectively, then their relation is
A) \frac{n_2}v-\frac{n_1}u=\frac{n_2-n_1}R
B) \frac{n_2}u-\frac{n_1}v=\frac{n_2-n_1}R
C) \frac{n_2}v-\frac{n_1}u=\frac{n_2-n_1}{2R}
D) \frac{n_2}u-\frac{n_1}v=\frac{n_2+n_1}R

View Answer
A) \frac{n_2}v-\frac{n_1}u=\frac{n_2-n_1}R

Q). An image is formed at a distance of 30 cm from the centre of convex lens of focal length 15 cm. The object distance is
A) 2 cm
B) 15 cm
C) 30 cm
D) 45 cm

View Answer
C) 30 cm
Explanation: Focal length of a convex lens = f = 15 cm
Object distance = u = – u = ?
Image distance = v = 30 cm
1/f = 1/v – 1/(-u) ⇒ 1/f = 1/v + 1/u
∴ 1/u =1/f- 1/v = 1/15 – 1/30 = 2-1/30 = 1/30
∴ u = 30 cm

Q). Which part of the human eye contains ‘rods’ and ‘cones’ to receive the light signals?
A) Cornea
B) Iris
C) Pupil
D) Retina

View Answer
D) Retina

Q). For a person with myopia defect, the image of the distant object is formed
A) before the retina
B) on the retina
C) beyond the retina
D) None

View Answer
A) before the retina

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