TS Polycet (Polytechnic) 2018 Previous Question Paper with Answers And Model Papers With Complete Analysis

Q). Least distance of distinct vision for normal eye is
A) 15 cm
B) 25 cm
C) 30 cm
D) 35 cm

View Answer
B) 25 cm

Q). Which lens is used to correct Myopia?
A) Convex
B) Concave
C) Cylindrical
D) None

View Answer
B) Concave

Q). Splitting of light into seven colours is called
A) Refraction
B) Reflection
C) Dispersion
D) Scattering

View Answer
C) Dispersion

Q). A prism with an angle of A = 60° produces a minimum deviation of30°. The refractive index of the material of the prism is
A) √2
B) 2
C) √3
D) 2 √2

View Answer
A) √2
Explanation: \mu\;=\;\frac{\sin\left({\displaystyle\frac{A+D}2}\right)}{\sin\left({\displaystyle\frac A2}\right)}\;=\;\frac{\sin\left({\displaystyle\frac{60+30}2}\right)}{\sin\left({\displaystyle\frac{60}2}\right)}
\frac{\sin\left(45^\circ\right)}{\sin\left(30^\circ\right)}=\frac{\displaystyle\frac1{\sqrt2}}{\displaystyle\frac12} = √2
∴ µ = √2

Q). Raman effect is related to which phenomenon of light?
A) Refraction
B) Reflection
C) Dispersion
D) Scattering

View Answer
D) Scattering

Q). Rainbow is formed due to……….. of light.
A) Refraction
B) Dispersion
C) Total internal reflection
D) All the above

View Answer
B) Dispersion
D) All the above

Q). S.I. unit of Electric current.
A) Volt
B) Ampere
C) Watt
D) Ohm

View Answer
B) Ampere

Q). Find the effective resistance of the combination between A and B.

A) (20/3)Ω
B) 20Ω
C) 10Ω
D) (3/20)Ω

View Answer
A) (20/3)Ω
Explanation: R1 = 2 + 8 = 10Ω
R2 = 6+ 14 = 20Ω
Effective resistance of the combination between A and B is
\frac1R=\frac1{R1}+\frac1{R2}=\frac1{10}+\frac1{20}=\frac{2+1}{20}
\frac1R=\frac3{20}\Rightarrow R\;=\frac{20}3\Omega

Q). Drift speed of electrons in an electric conductor is
A) 7 mm/s
B) 70 mm/s
C) 0.07 mm/s
D) None

View Answer
C) 0.07 mm/s

Q). The resistance of conductor depends on
A) length of conductor
B) area of cross section of conductor
C) nature of the substance of conductor
D) all the above

View Answer
D) all the above

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