TS Polycet (Polytechnic) 2020 Previous Question Paper with Answers And Model Papers With Complete Analysis

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Q) logxb – logxa = logxc – logxb
∴ ac =
A) a2
B) b2
C) c2
D) None

View Answer
B) b2
Explanation: logxb – logxa = logxc – logxb
=> logx(b/a) = logx(c/b)
=>b/a = c/b=> b2 = ac

Q) A = {P, O, L, Y, T, E, C, H, N, 1, Q}, B = {P, O, L, Y, C, E, T, 2020}, B – A =
A) {20}
B) {2020}
C) {40}
D) None

View Answer
B) {2020}
Explanation: A = {P, O, L, Y, T, E; C, H, N, I, Q} B = {P, O, L, Y, C, E, t 2020}
B -A = {P, O,- L, Y, C, E, T, 2020} -{P, 6, L, Y, T, E, C, H, N, I, Q)
= {2020}

Q) If (5, 2) is the solution of 2x + 5y = 20, ax -by = 0, then (a, b) =
A) (2, 5)
B) (5, 2)
C) (-2, 5)
D) (-5, 2)

View Answer
A) (2, 5)
Explanation: (5, 2) is the solution of
2x + 5y = 20, ax – by = 0, then
5a-2b = 0
Verify option (1)
(2, 5) =>5(2)-2(5) = 10-10 = 0

Q) If the system of equations x – y = 1, ax + y = 2 has unique solution, then
A) a = 1
B) a = -1
C) a ≠ 1
D) a ≠ -1

View Answer
D) a ≠ -1
Explanation: a1/a2≠b1/b2
=> 1/a ≠ -1/1 =>1/a ≠ -1 =>A ≠ 1

Q) If α, β are the roots of x2– 1 = 0, then α+ β =
A) 0
B) 1
C) -1
D) 2

View Answer
A) 0
Explanation: b2 — 1 = 0
a = 1, b = 0, c = —1
α + β = -b/a = – 0/1 = 0

Q) For the equation 2019x+2020y = 4040 when x = 0 the value of y =
A) 2020
B) 2019
C) 4
D) 2

View Answer
D) 2
Explanation: 2019x + 2020y = 4040
: x = 0 => 2019 (0) + 2020y = 4040
=>2020y=4040
=> y = 4040/2020 = 2

Q) Solution of the equations 7x + 5y = 12, 5x – 7y = -2 is not equal to
A) \frac{-22}{22}. \frac{14}{14}

View Answer
A) \frac{-22}{22}. \frac{14}{14}

Q) From the top of the tower 60 mts high the angle of depression of two objects due north and due south of the tower are 60° and 45°, then the distance between two objects is
A) 60 √3 m
B) ( 60+20 √3)m
C) (60+ √3-1)m
D) (60+ √3+1)m

View Answer
B) ( 60+20 √3)m
Explanation: In △ACD,
Tan 60° = CD/AC
√3 = 60/AC

=> AC = 60/√3 = 20√3m
In △BCD,
Tan 45° = CD/BC
1 = 60/BC => BC = 60m
∴ AB = AC + BC = ( 20+√3 + 60)m

Q) What is the probability of getting an even number in a single throw of a die?
A) \frac12

View Answer
A) \frac12

Q) Find the mode when median is 125.6 and mean is 128.
A) 120
B) 120.8
C) 125
D) 128

View Answer
B) 120.8
Explanation: Mode = ?
Median = 125.6
Mean = 128
∴ Mode.= 3 median – 2 mean
= 3(125.6)-2(128)
= 376.8 – 256
= 120.8
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